30u^2+78u+48=0

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Solution for 30u^2+78u+48=0 equation:



30u^2+78u+48=0
a = 30; b = 78; c = +48;
Δ = b2-4ac
Δ = 782-4·30·48
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(78)-18}{2*30}=\frac{-96}{60} =-1+3/5 $
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(78)+18}{2*30}=\frac{-60}{60} =-1 $

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